Since all engines are producing work by manipulating a fluid (air in our case), we can relate the power (P) to the pressure (p) and the volumetric flow rate (Q):
P = pQ  (1) 
Because in an engine p and Q are varying constantly throughout a cycle, we must used average values.
For any engine, you can find the power at the crankshaft output with the brake mean effective differential pressure (BMEP_{d}) and the measured volumetric flow rate (Q_{m}):
P = BMEP_{d} Q_{m}  (2) 
In addition, for a reciprocating engine or a rotary combustion engine you can find the power at the crankshaft output with the brake mean effective pressure (BMEP) and the theoritical volumetric flow rate (Q_{th}):
P = BMEP Q_{th}  (3) 
Example
If you want your engine to produce 74 600 W) and you know that similar engines produce (1 000 000 Pa) of BMEP_{d}, then you will need to displace 158 (0.075 m³/s) of air.
(This is true no matter what type of engine it is. It could be a turboshaft engine, a Wankel engine, a piston engine (4stroke, 2stroke; SI or CI) with or without forced induction or any other type of engine you can think of.
Torque
For any reciprocating engine or rotary combustion engine, you can define its torque ( T ) with the following: (more)

(4) 
Where V_{θ} is the amount of air displaced per angular displacement of the output shaft (m³/rad).
The reason torque is introduced in this page about power, is to show that:
Engine torque does not represent the engine's potential
In fact, if you want to know the potential of your vehicle, all you need to know is the power output of the engine, not the torque (see acceleration simulator).
For example, let's say we have an engine that displaces 3 L (0.003 m³) of air for each cycle, with a BMEP of 10 bar (1 000 000 Pa). If the engine is a 4stroke, it completes a cycle in 2 revolutions (4
Let's also imagine that this engine is connected to a wheel via a gearbox with a gear ratio of 3:1. So every time the engine makes 3 revolutions, the wheel makes only 1 revolution. That means that the wheel makes 2/3 revolution (4
So we can find the engine crankshaft torque (T_{e}) and the wheel torque (T_{w}) with equation (4):





Even if the engine was a 2stroke − and completed one cycle in 1 revolution (2





So even if the engine torque is twice as big,
the wheel displacement and the wheel torque are the same for one engine cycle
Hence, the vehicle wouldn't see a difference.